2x^2-10x+53=0

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Solution for 2x^2-10x+53=0 equation: 



2x^2-10x+53=0

a = 2; b = -10; c = +53;
Δ = b2-4ac
Δ = -102-4·2·53
Δ = -324
Delta is less than zero, so there is no solution for the equation

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